Prediction (out of sample)

[1]:
%matplotlib inline
[2]:
import numpy as np
import matplotlib.pyplot as plt

import statsmodels.api as sm

plt.rc("figure", figsize=(16, 8))
plt.rc("font", size=14)

Artificial data

[3]:
nsample = 50
sig = 0.25
x1 = np.linspace(0, 20, nsample)
X = np.column_stack((x1, np.sin(x1), (x1 - 5) ** 2))
X = sm.add_constant(X)
beta = [5.0, 0.5, 0.5, -0.02]
y_true = np.dot(X, beta)
y = y_true + sig * np.random.normal(size=nsample)

Estimation

[4]:
olsmod = sm.OLS(y, X)
olsres = olsmod.fit()
print(olsres.summary())
                            OLS Regression Results
==============================================================================
Dep. Variable:                      y   R-squared:                       0.982
Model:                            OLS   Adj. R-squared:                  0.980
Method:                 Least Squares   F-statistic:                     815.6
Date:                Sat, 09 Jul 2022   Prob (F-statistic):           7.18e-40
Time:                        10:15:30   Log-Likelihood:                -2.3645
No. Observations:                  50   AIC:                             12.73
Df Residuals:                      46   BIC:                             20.38
Df Model:                           3
Covariance Type:            nonrobust
==============================================================================
                 coef    std err          t      P>|t|      [0.025      0.975]
------------------------------------------------------------------------------
const          5.0717      0.090     56.259      0.000       4.890       5.253
x1             0.4952      0.014     35.619      0.000       0.467       0.523
x2             0.4595      0.055      8.408      0.000       0.350       0.570
x3            -0.0193      0.001    -15.798      0.000      -0.022      -0.017
==============================================================================
Omnibus:                        2.101   Durbin-Watson:                   2.156
Prob(Omnibus):                  0.350   Jarque-Bera (JB):                1.443
Skew:                          -0.407   Prob(JB):                        0.486
Kurtosis:                       3.169   Cond. No.                         221.
==============================================================================

Notes:
[1] Standard Errors assume that the covariance matrix of the errors is correctly specified.

In-sample prediction

[5]:
ypred = olsres.predict(X)
print(ypred)
[ 4.58961885  5.0496539   5.47329499  5.83549733  6.12025464  6.323229
  6.45246349  6.52706077  6.57404458  6.62391979  6.70566054  6.84194988
  7.04545302  7.31673644  7.64417483  8.00586112  8.37320572  8.71563374
  9.0056083   9.22315483  9.3591428   9.41678584  9.41111375  9.36650317
  9.31267251  9.27979939  9.29356245  9.37092247  9.51733577  9.72585771
  9.97828373 10.24814025 10.50503425 10.71964674 10.86854978 10.93805563
 10.92646561 10.8443492  10.71280746 10.56000625 10.4165486  10.31044676
 10.26251984 10.28297331 10.36972225 10.5087339  10.67633324 10.84309266
 10.9786669  11.05677863]

Create a new sample of explanatory variables Xnew, predict and plot

[6]:
x1n = np.linspace(20.5, 25, 10)
Xnew = np.column_stack((x1n, np.sin(x1n), (x1n - 5) ** 2))
Xnew = sm.add_constant(Xnew)
ynewpred = olsres.predict(Xnew)  # predict out of sample
print(ynewpred)
[11.04885439 10.91913205 10.68563323 10.38942693 10.0845744   9.82489304
  9.65078008  9.57932186  9.60011056  9.67779235]

Plot comparison

[7]:
import matplotlib.pyplot as plt

fig, ax = plt.subplots()
ax.plot(x1, y, "o", label="Data")
ax.plot(x1, y_true, "b-", label="True")
ax.plot(np.hstack((x1, x1n)), np.hstack((ypred, ynewpred)), "r", label="OLS prediction")
ax.legend(loc="best")
[7]:
<matplotlib.legend.Legend at 0x7fbd605cc790>
../../../_images/examples_notebooks_generated_predict_12_1.png

Predicting with Formulas

Using formulas can make both estimation and prediction a lot easier

[8]:
from statsmodels.formula.api import ols

data = {"x1": x1, "y": y}

res = ols("y ~ x1 + np.sin(x1) + I((x1-5)**2)", data=data).fit()

We use the I to indicate use of the Identity transform. Ie., we do not want any expansion magic from using **2

[9]:
res.params
[9]:
Intercept           5.071725
x1                  0.495223
np.sin(x1)          0.459545
I((x1 - 5) ** 2)   -0.019284
dtype: float64

Now we only have to pass the single variable and we get the transformed right-hand side variables automatically

[10]:
res.predict(exog=dict(x1=x1n))
[10]:
0    11.048854
1    10.919132
2    10.685633
3    10.389427
4    10.084574
5     9.824893
6     9.650780
7     9.579322
8     9.600111
9     9.677792
dtype: float64