# Tests that '@' is recognized as an Operator

---input---
S = (H @ beta - r).T @ inv(H @ V @ H.T) @ (H @ beta - r)

---tokens---
'S'           Name
' '           Text
'='           Operator
' '           Text
'('           Punctuation
'H'           Name
' '           Text
'@'           Operator
' '           Text
'beta'        Name
' '           Text
'-'           Operator
' '           Text
'r'           Name
')'           Punctuation
'.'           Operator
'T'           Name
' '           Text
'@'           Operator
' '           Text
'inv'         Name
'('           Punctuation
'H'           Name
' '           Text
'@'           Operator
' '           Text
'V'           Name
' '           Text
'@'           Operator
' '           Text
'H'           Name
'.'           Operator
'T'           Name
')'           Punctuation
' '           Text
'@'           Operator
' '           Text
'('           Punctuation
'H'           Name
' '           Text
'@'           Operator
' '           Text
'beta'        Name
' '           Text
'-'           Operator
' '           Text
'r'           Name
')'           Punctuation
'\n'          Text.Whitespace
